{"id":9242,"date":"2021-06-18T14:40:08","date_gmt":"2021-06-18T07:40:08","guid":{"rendered":"https:\/\/metmar.net\/?p=9242"},"modified":"2021-08-10T10:32:16","modified_gmt":"2021-08-10T03:32:16","slug":"chuong-trinh-dao-tao-dieu-duong","status":"publish","type":"post","link":"https:\/\/metmar.net\/chuong-trinh-dao-tao-dieu-duong\/","title":{"rendered":"Ch\u01b0\u01a1ng tr\u00ecnh \u0111\u00e0o t\u1ea1o \u0111i\u1ec1u d\u01b0\u1ee1ng"},"content":{"rendered":"
\u00a0 <\/span><\/strong><\/p>\n <\/p>\n \u0110\u00e0o t\u1ea1o C\u1eed nh\u00e2n \u0110i\u1ec1u d\u01b0\u1ee1ng<\/strong> c\u00f3 ph\u1ea9m ch\u1ea5t ch\u00ednh tr\u1ecb t\u1ed1t, c\u00f3 \u0111\u1ea1o \u0111\u1ee9c ngh\u1ec1 <\/span>nghi\u1ec7p, c\u00f3 \u00fd th\u1ee9c ph\u1ee5c v\u1ee5 nh\u00e2n d\u00e2n, c\u00f3 ki\u1ebfn th\u1ee9c v\u00e0 k\u1ef9 n\u0103ng th\u1ef1c h\u00e0nh \u0111\u00e1p \u1ee9ng c\u00e1c <\/span>chu\u1ea9n n\u0103ng l\u1ef1c \u0110i\u1ec1u d\u01b0\u1ee1ng Vi\u1ec7t Nam<\/strong> \u1edf tr\u00ecnh \u0111\u1ed9 \u0111\u1ea1i h\u1ecdc, c\u00f3 s\u1ee9c kh\u1ecfe, c\u00f3 kh\u1ea3 n\u0103ng l\u00e0m <\/span>vi\u1ec7c \u0111\u1ed9c l\u1eadp, s\u00e1ng t\u1ea1o, t\u1ef1 h\u1ecdc v\u00e0 nghi\u00ean c\u1ee9u khoa h\u1ecdc nh\u1eb1m \u0111\u00e1p \u1ee9ng nhu c\u1ea7u b\u1ea3o v\u1ec7, <\/span>ch\u0103m s\u00f3c v\u00e0 n\u00e2ng cao s\u1ee9c kh\u1ecfe c\u1ed9ng \u0111\u1ed3ng.<\/span><\/p>\n I. M\u1ee4C TI\u00caU C\u1ee4 TH\u1ec2<\/span><\/strong><\/p>\n (H\u1ed9i nh\u1eadp v\u00f3i 18 ti\u00eau chu\u1ea9n n\u0103ng l\u1ef1c c\u1ee7a C\u1eed nh\u00e2n \u0110i\u1ec1u d\u01b0\u1ee1ng \u0110\u00f4ng Nam \u00c1 v\u00e0 T\u00e2y <\/span>Th\u00e1i B\u00ecnh D\u01b0\u01a1ng) trong c\u00f4ng t\u00e1c ch\u0103m s\u00f3c ng\u01b0\u1eddi b\u1ec7nh, c\u00f4ng t\u00e1c qu\u1ea3n l\u00fd di\u1ec1u d\u01b0\u1ee1ng <\/span>v\u00e0 h\u00e0nh ngh\u1ec1 \u0110i\u1ec1u d\u01b0\u1ee1ng.<\/span><\/p>\n \u00a0 \u00a0 \u00a0 2. K\u1ef9 n\u0103ng<\/strong><\/span><\/p>\n + K\u1ef9 n\u0103ng c\u1ee9ng: N\u0103ng l\u1ef1c th\u1ef1c h\u00e0nh (theo chu\u1ea9n n\u0103ng l\u1ef1c c\u1ee7a c\u1eed nh\u00e2n \u0110i\u1ec1u <\/span>d\u01b0\u1ee1ng Vi\u1ec7t Nam do B\u1ed9 Y t\u1ebf ban h\u00e0nh th\u00e1ng 4\/2012): g\u1ed3m 3 l\u0129nh v\u1ef1c, 25 chu\u1ea9n n\u0103ng l\u1ef1c, <\/span>1 l\u00f4 ti\u00eau ch\u00ed<\/span><\/p>\n + N\u0103ng l\u1ef1c t\u1ec3 ch\u1ee9c qu\u1ea3n l\u00fd.<\/span><\/p>\n + N\u0103ng l\u1ef1c ph\u00e1t hi\u1ec7n s\u1edbm d\u1ecbch b\u1ec7nh: t\u1ea1i \u0111\u1ecba ph\u01b0ong v\u00e0 t\u00edch c\u1ef1c tham gia ch\u1ed1ng d\u1ecbch<\/span><\/p>\n + K\u1ef9 n\u0103ng m\u1ec1m:<\/span><\/p>\n + V\u1ec1 ngo\u1ea1i ng\u1eef: \u0110\u1ea1t tr\u00ecnh \u0111\u1ed9 IELTS 4.5 ho\u1eb7c t\u01b0\u01a1ng \u0111\u01b0\u01a1ng<\/span><\/p>\n + V\u1ec1 tin h\u1ecdc: C\u00f3 k\u1ef9 n\u0103ng c\u01a1 b\u1ea3n v\u1ec1 c\u00f4ng ngh\u1ec7 th\u00f4ng tin v\u00e0 v\u1eadn d\u1ee5ng trong l\u0129nh <\/span>v\u1ef1c chuy\u00ean m\u00f4n;<\/span><\/p>\n \u00a0 \u00a0 \u00a0 \u00a03. Th\u00e1i \u0111\u1ed9<\/span><\/strong><\/p>\n Th\u1ef1c hi\u1ec7n \u0111\u1ea7y \u0111\u1ee7 12 \u0111i\u1ec1u Y \u0111\u1ee9c:<\/span><\/p>\n II. \u0110I\u1ec0U KI\u1ec6N TUY\u1ec2N SINH<\/strong><\/span><\/p>\n T\u1ed5 h\u1ee3p x\u00e9t tuy\u1ec3n<\/strong>:<\/span><\/p>\n Tuy\u1ec3n sinh tr\u00ean to\u00e0n qu\u1ed1c ng\u00e0nh C\u1eed nh\u00e2n \u0110i\u1ec1u d\u01b0\u1ee1ng<\/span><\/p>\n H\u1ed3 s\u01a1 \u0111\u0103ng k\u00ed g\u1ed3m c\u00f3 gi\u1ea5y khai sinh photo c\u00f4ng ch\u1ee9ng, ch\u1ee9ng minh th\u01b0 photo c\u00f4ng ch\u1ee9ng, \u1ea3nh 3×4<\/span><\/p>\n B\u1eb1ng v\u00e0 b\u1ea3ng \u0111i\u1ec3m khi n\u00e0o c\u00f3 b\u1ed5 sung sau<\/span><\/p>\n \u0110i\u1ec3m XT \u00a0= TBC l\u1edbp 10 + TBC l\u1edbp 11 + HK1 l\u1edbp 12 + \u0111i\u1ec3m \u01b0u ti\u00ean \u2265 18.0<\/span><\/p>\n \u0110i\u1ec3m XT = HK1 l\u1edbp 11 + HK2 l\u1edbp 11 + HK1 l\u1edbp 12 + \u0111i\u1ec3m \u01b0u ti\u00ean \u2265 18.0<\/span><\/p>\n \u0110i\u1ec3m XT = \u0110TB m\u00f4n 1 + \u0110TB m\u00f4n 2 + \u0110TB m\u00f4n 3 + \u0111i\u1ec3m \u01b0u ti\u00ean \u2265 18.0<\/span><\/p>\n \u0110i\u1ec3m XT = \u0110TB m\u00f4n 1 + \u0110TB m\u00f4n 2 + \u0110TB m\u00f4n 3 + \u0111i\u1ec3m \u01b0u ti\u00ean \u2265 18.0<\/span><\/p>\n \u0110i\u1ec3m XT = T\u1ed5ng \u0111i\u1ec3m thi 3 m\u00f4n\/ t\u1ed5 h\u1ee3p + \u0110i\u1ec3m \u01b0u ti\u00ean<\/span><\/p>\n \u0110i\u1ec3m XT = T\u1ed5ng \u0111i\u1ec3m m\u00f4n t\u1ed5 h\u1ee3p + \u0110i\u1ec3m thi n\u0103ng khi\u1ebfu + \u0110i\u1ec3m \u01b0u ti\u00ean<\/span><\/p>\n Theo quy ch\u1ebf c\u1ee7a B\u1ed9 GD & \u0110T v\u00e0o t\u1ea5t c\u1ea3 c\u00e1c ng\u00e0nh \u0111\u00e0o t\u1ea1o c\u1ee7a tr\u01b0\u1eddng<\/span><\/p>\n X\u00e9t tuy\u1ec3n th\u00ed sinh t\u1ed1t nghi\u1ec7p th\u00ed sinh t\u1ed1t nghi\u1ec7p THPT c\u00f3 h\u1ecdc l\u1ef1c l\u1edbp 12 x\u1ebfp lo\u1ea1i gi\u1ecfi ho\u1eb7c \u0111i\u1ec3m trung b\u00ecnh x\u00e9t t\u1ed1t nghi\u1ec7p THPT t\u1eeb 6.5 tr\u1edf l\u00ean.<\/span><\/p>\n * Ch\u00fa \u00fd:<\/strong> \u0111i\u1ec3m x\u00e9t tr\u00fang tuy\u1ec3n v\u00e0o tr\u01b0\u1eddng s\u1ebd \u0111\u01b0\u1ee3c c\u00f4ng b\u1ed1 sau khi c\u00f3 k\u1ebft qu\u1ea3 K\u1ef3 thi THPT<\/em><\/span><\/p>\n TT<\/strong><\/p>\n<\/td>\n Kh\u1ed1i l\u01b0\u1ee3ng h\u1ecdc t\u1eadp<\/strong><\/p>\n<\/td>\n CH\u1ec8<\/strong><\/td>\n<\/tr>\n\n
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\n KH\u1ed4I L\u01af\u1ee2NG KI\u1ebeN TH\u1ee8C<\/strong>: 135 t\u00edn ch\u1ec9 (kh\u00f4ng bao g\u1ed3m Gi\u00e1o d\u1ee5c th\u1ec3 ch\u1ea5t v\u00e0 Gi\u00e1o d\u1ee5c qu\u1ed1c ph\u00f2ng)<\/p>\n \n\n
\n \n \n T\u00cdN<\/strong><\/p>\n \n